3^((x^2)+4x)=1/27

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Solution for 3^((x^2)+4x)=1/27 equation: 



3^((x^2)+4x)=1/27

We move all terms to the left:

3^((x^2)+4x)-(1/27)=0

We add all the numbers together, and all the variables

3^(x^2+4x)-(+1/27)=0

We get rid of parentheses

3^(x^2+4x)-1/27=0

We multiply all the terms by the denominator


(3^(x^2+4x))*27-1=0

We move all terms containing x to the left, all other terms to the right

(3^(x^2+4x))*27=1

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